Chapter 7

1.	Dictionary methods dict.update()
3.	Dictionary methods keys = dict.keys() keys.sort() or sorted(dict.keys())
4.	Creating dictionaries # assumes and list2 are the same length d = {} for i in range(len(list1)): d[list1[i]] = list2[i] or d = {} for i, x in enumerate(list1): d[x] = list2[i] or d = dict(map(None, list1, list2)) or d = dict(zip(list1, list2))
7.	Inverting dictionaries list1 = oldDict.values() list2 = oldDict.keys() Now apply the solutions to Problem 4. Note that these solutions are destructive, meaning that for one-to-many dictionaries, keys that share the same values will only have the latest installed value for the value that is now a key. Extra Credit: Come up with a non-destructive solution where keys that share the same values in the old dictionary are now stored inside a list as the value for the corresponding key in the new dictionary.