Indexes
The problem of listing indexes for a table is much the same as that of listing constraints on a table. You have a master-detail relationship between the index and its columns , and you may have multiple indexes on one table.
To list only the indexes on a table, query the all_indexes view:
SELECT index_name, index_type, uniqueness
FROM all_indexes
WHERE owner = UPPER('&owner')
AND table_name = UPPER('&table_name');
Listing the indexes alone is seldom enough. You need to know at least the columns involved in each index. To that end, join with all_ind_columns . Example 10-8 shows the query.
Example 10-8. A script to list all indexes on a table
COLUMN index_name FORMAT A20
COLUMN index_type FORMAT A10
COLUMN UNIQUENESS FORMAT A10
COLUMN column_name FORMAT A15
SELECT ai.index_name, ai.index_type, ai.uniqueness, aic.column_name
FROM all_indexes ai INNER JOIN all_ind_columns aic
ON ai.owner = aic.index_owner
AND ai.index_name = aic.index_name
WHERE ai.owner = UPPER('&owner')
AND ai.table_name = UPPER('&table_name')
ORDER BY aic.column_position;
Here's a run of Example 10-8 showing the two indexes on the employee table:
SQL>
@ex10-8
Enter value for owner:
gennick
old 5: WHERE ai.owner = UPPER('&owner')
new 5: WHERE ai.owner = UPPER('gennick')
Enter value for table_name:
employee
old 6: AND ai.table_name = UPPER('&table_name')
new 6: AND ai.table_name = UPPER('employee')
INDEX_NAME INDEX_TYPE UNIQUENESS COLUMN_NAME
-------------------- ---------- ---------- ---------------
EMPLOYEE_PK NORMAL UNIQUE EMPLOYEE_ID
EMPLOYEE_BY_NAME NORMAL NONUNIQUE EMPLOYEE_NAME
One thing to keep in mind when working with unique indexes is that Oracle will report a unique index violation as if it were a constraint violation. The error message you get is the same as the one used when you violate a unique constraint, and it looks like this:
ORA-00001: unique constraint (GENNICK.UNIQUE_BILLING_RATE) violated
The reason for this is no doubt because Oracle enforces unique and primary key constraints by creating indexes on the constrained fields. If you do get the error message just shown, you might want to check two things. First, list the constraints on the table you are updating. Second, if you don't find one with a name that matches the one in the error message, check to see whether there happens to be a unique index with that same name .
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