5.2 Using this-

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5.2 Using this->

For class templates with base classes, using a name x by itself is not always equivalent to this->x , even though a member x is inherited. For example:

 template <typename T>  class Base {    public:      void exit();  }; template <typename T>  class Derived : Base<T> {    public:      void foo() {          exit();  // calls external  exit()  or error  }  }; 

In this example, for resolving the symbol exit inside foo() , exit() defined in Base is never considered . Therefore, either you have an error, or another exit() (such as the standard exit() ) is called.

We discuss this issue in Section 9.4.2 on page 136 in detail. For the moment, as a rule of thumb, we recommend that you always qualify any symbol that is declared in a base that is somehow dependent on a template parameter with this-> or Base<T>:: . If you want to avoid all uncertainty, you may consider qualifying all member accesses (in templates).

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