Recipe 5.42. Using Regular Expressions to Count Characters, Words, or Lines


Problem

You want to count the characters, words, and lines in a string.

Solution

Sample code folder: Chapter 05\RegexCountParts

Use separate regular expressions to count words, characters, and lines in a string of any length.

Discussion

The following code demonstrates three very short regular expressions that provide simple counts of characters, words, and lines in a string of any length:

 Imports System.Text.RegularExpressions ' …Later, in a method… Dim quote As String = _    "The important thing" & vbNewLine & _    "is not to stop questioning." & vbNewLine & _    "--Albert Einstein" & vbNewLine Dim numBytes As Integer = quote.Length * 2 Dim numChars As Integer = Regex.Matches(quote, ".").Count Dim numWords As Integer = Regex.Matches(quote, "\w+").Count Dim numLines As Integer = Regex.Matches(quote, ".+\n*").Count MsgBox(String.Format( _    "{0}{5}bytes: {1}{5}Chars: {2}{5}Words: {3}{5}Lines: {4}", _    quote, numBytes, numChars, numWords, numLines, vbNewLine)) 

The number of bytes in the string is also displayed, as shown in Figure 5-50, but the string's Length property provides this count directly without having to resort to a regular expression.

Figure 5-50. Using simple regular expressions to count characters, words, or lines in a string


See Also

Recipe 5.38 also discusses the results of regular expression processing.




Visual Basic 2005 Cookbook(c) Solutions for VB 2005 Programmers
Visual Basic 2005 Cookbook: Solutions for VB 2005 Programmers (Cookbooks (OReilly))
ISBN: 0596101775
EAN: 2147483647
Year: 2006
Pages: 400

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