112.

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Page 199

Figure 5.8 (a) A 3×3 window of grey level values is shown on the left. In the centre the same data are depicted as an intensity surface with the corner pixels shaded. Interpolation of the central pixel (= (20+16+10+10)/4=14) is shown on the right. Four triangular facets are formed, (b) To obtain the triangular area with vertices a, c, and d, one possible way is to resolve then substitute in Equation (5.14). See text for derivation.

(5.15)

In Equation (5.15), becomes a function of vertices a, c and d. Since the co-ordinates of these three vertices are already known, is resolvable, and each triangular area can be computed using Equation (5.14). The algorithm

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